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x^2+12x^2-3x-630=0
We add all the numbers together, and all the variables
13x^2-3x-630=0
a = 13; b = -3; c = -630;
Δ = b2-4ac
Δ = -32-4·13·(-630)
Δ = 32769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32769}=\sqrt{9*3641}=\sqrt{9}*\sqrt{3641}=3\sqrt{3641}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{3641}}{2*13}=\frac{3-3\sqrt{3641}}{26} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{3641}}{2*13}=\frac{3+3\sqrt{3641}}{26} $
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